5r^2+17r-40=0

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Solution for 5r^2+17r-40=0 equation:


Simplifying
5r2 + 17r + -40 = 0

Reorder the terms:
-40 + 17r + 5r2 = 0

Solving
-40 + 17r + 5r2 = 0

Solving for variable 'r'.

Factor a trinomial.
(-5 + -1r)(8 + -5r) = 0

Subproblem 1

Set the factor '(-5 + -1r)' equal to zero and attempt to solve: Simplifying -5 + -1r = 0 Solving -5 + -1r = 0 Move all terms containing r to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1r = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1r = 0 + 5 -1r = 0 + 5 Combine like terms: 0 + 5 = 5 -1r = 5 Divide each side by '-1'. r = -5 Simplifying r = -5

Subproblem 2

Set the factor '(8 + -5r)' equal to zero and attempt to solve: Simplifying 8 + -5r = 0 Solving 8 + -5r = 0 Move all terms containing r to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -5r = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -5r = 0 + -8 -5r = 0 + -8 Combine like terms: 0 + -8 = -8 -5r = -8 Divide each side by '-5'. r = 1.6 Simplifying r = 1.6

Solution

r = {-5, 1.6}

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